Предмет: Математика, автор: Аноним

2. а) Разложи на сумму разрядных слагаемых числа: 28, 39, 54.
б) Вычисли.
20 + (3 + 5)
30 + (2 + 7) 50 + (3 + 6)
30 + (7 – 2)
50 + (6 – 4) 40 + (9 – 5)
40 + (8 - 2)
20 + (2 + 6) 70 + (7 — 6)
30 + (5+4)
80 + (3 – 2)
70 + (5 – 4)​

Ответы

Автор ответа: zarabitemir
7

Ответ:

а)

28=20+8

39=30+9

54=50+4

Пошаговое объяснение:

б)

20+(3+5)=28

30+(2+7)=39

50+(3+6)=59

30+(7-2)=35

50+(6-4)=52

40+(9-5)=44

40+(8-2)=46

20+(2+6)=28

70+(7-6)=71

30+(5+4)=39

80+(3-2)=81

70+(5-4)=71

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