Предмет: Математика, автор: hdkakhx

найдите площадь закрашенной части фигуры,если радиус круга 11 см,а сторона квадрата 5 см.
ПОМОГИТЕ ПРОШУ

Приложения:

nanoonan16th: да

Ответы

Автор ответа: nanoonan16th

2

Ответ: 354,94 см^2

Пошаговое объяснение:

Sкруга= $\pi r^2=3.14*11^2=379,94$

Sквадрата= $a^2=5^2=25$

Sзакрашенной=Sкруга-Sквадрата=379.94-25=354,94 см^2

hdkakhx: спасибо!!!это правильно?

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