Помогите решить
1,2(3-x) - 0,3(4x + 1) = 0,1 - 0,8(3x - 4) ​

Ответ:

1,2(3-х)-0,3(4х+1)=0,1-0,8(3х-4)

1,2(3-х)-0,3(4х+1)=0,1-0,8(3х-4)3,6-1,2-1 2х-0,3=0,1-2,4х+3,2

1,2(3-х)-0,3(4х+1)=0,1-0,8(3х-4)3,6-1,2-1 2х-0,3=0,1-2,4х+3,23,3-2,4х=3,3-2,4х

1,2(3-х)-0,3(4х+1)=0,1-0,8(3х-4)3,6-1,2-1 2х-0,3=0,1-2,4х+3,23,3-2,4х=3,3-2,4х-2,4х+2,4х=3,3-3,3

1,2(3-х)-0,3(4х+1)=0,1-0,8(3х-4)3,6-1,2-1 2х-0,3=0,1-2,4х+3,23,3-2,4х=3,3-2,4х-2,4х+2,4х=3,3-3,30=0