Предмет: Геометрия, автор: chumachenka9

ОЧЕНЬ СРОЧНО!!!!!!!!!
У трикутнику АВС АВ =9 см, АС =6см і ВС = 5см. У якому. відношенні центр кола, вписаного у трикутник АВС, ділить бісектрису трикутника АN?

Ответы

Автор ответа: mathkot

Ответ:

Центр кола, вписаного у трикутник АВС, ділить бісектрису трикутника АN

у відношенні 3 : 1

Объяснение:

Смотрите фотографии.

Приложения:

glazkovvvvkiril: Дякую!!!!!!Від серця!!!!

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ОЧЕНЬ СРОЧНО!!!!!!!!! У трикутнику АВС АВ =9 см, АС =6см і ВС = 5см. У якому. відношенні центр кола, вписаного у трикутник АВС, ділить бісектрису трикутника АN? ​

Ответы

ОЧЕНЬ СРОЧНО!!!!!!!!!
У трикутнику АВС АВ =9 см, АС =6см і ВС = 5см. У якому. відношенні центр кола, вписаного у трикутник АВС, ділить бісектрису трикутника АN?