Предмет: Геометрия, автор: ПППРПП

Найдите высоту прямоугольного треугольника, если она проведена к гипотенузе и делит ее на отрезкы, которые равны 3 см и 12 см

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Автор ответа: volkodav575

Высота прямоугольного треугольника, опущенная на гипотенузу, равна среднему геометрическому проекций катетов на гипотенузу, значит:
$h = sqrt{3*12}= sqrt{36}=6$

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