Предмет: Алгебра, автор: ladyselkova

√2cos^2x=sin(п/2+x) помогите пожалуйста))

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Автор ответа: uekmyfhfp

sgrt2*cos^2(x)=cosx sgrt2*cos^2(x)-cosx=0 cosx*(sgrt2*cosx-1)=0 1)cosx=0; x= pi/2 +2pik. 2) sgrt2 *cosx -1=0; cosx=1/sgrt2=sgrt2/2 x=+-pi/4 +2pi*k

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