Предмет: Математика, автор: kozumekenmahaikyuu

срочно пожалуйста,желательно на тетрадке:))

Приложения:

Ответы

Автор ответа: ksyuwi

( 1 )

$\left \{ {{x>1} \atop {x>2,5}} \right.$

x ∈ ( 2,5 ; +∞ )

( 2 )

$\left \{ {{-2x\leq-3} \atop {x\leq 3}} \right. \\\\\left \{ {{x\leq -3:(-2)} \atop {x\leq 3}} \right. \\\\\left \{ {{x\geq 1,5} \atop {x\leq 3}} \right.$

x ∈ [ 1,5 ; 3 ]

( 3 )

$\left \{ {{x<-1,5} \atop {x>-2}} \right. \\$

x ∈ ( -2 ; -1,5 )

( 4 )

$\left \{ {{4-5x>-1} \atop {\frac{1}{6}x<2 }} \right. \\\\\left \{ {{-5x>-1-4} \atop {x<2:\frac{1}{6} }} \right.\\\\\left \{ {{-5x>-5} \atop {x<2*\frac{6}{1} }} \right.\\\\\left \{ {{x<-5:(-5)} \atop {x<\frac{12}{1} }} \right. \\\\\left \{ {{x<1} \atop {x<12}} \right.$

x ∈ ( -∞ ; 1 )

( 5 )

$\left \{ {{0,6x\leq 9} \atop {\frac{1}{3} x\geq 2}} \right.\\\\\left \{ {{x\leq 9:0,6} \atop {x\geq 2:\frac{1}{3} }} \right. \\\\\left \{ {{x\leq 15} \atop {x\geq 2*\frac{3}{1} }} \right.\\\\\left \{ {{x\leq 15} \atop {x\geq 2*3 }} \right.\\\\\left \{ {{x\leq 15} \atop {x\geq 6}} \right.\\$

x ∈ [ 6 ; 15 ]

( 6 )

$\left \{ {{9x>0} \atop {\frac{1}{7}x\geq -1 }} \right. \\\\\left \{ {{x>0:9} \atop {x\geq -1:\frac{1}{7} }} \right.\\\\\left \{ {{x>0} \atop {x\geq -1*\frac{7}{1} }} \right. \\\\\left \{ {{x>0} \atop {x\geq -1*7}} \right. \\\\\left \{ {{x>0} \atop {x\geq -7}} \right.$