Предмет: Алгебра, автор: Аноним

СРОЧНО ПОМОГИТЕ ПОЖАЛУЙСТА ПРОШУУУ СРОЧНО ПОЖАЛУЙСТА

Приложения:

Ответы

Автор ответа: Orangesss

2

Ответ и объяснение:

$A)\ \dfrac{x+y}{5y} -\dfrac{x-y}{5y} = \dfrac{x+y-(x-y)}{5y} = \dfrac{x+y-x+y}{5y} = \dfrac{2y}{5y} = \dfrac{2}{5} = 0,4.\\\\B)\ \dfrac{3^{/b-a}}{b+a}+\dfrac{5^{/b+a}}{b-a} = \dfrac{3(b-a)+5(b+a)}{(b+a)(b-a)} = \dfrac{3b-3a+5b+5a}{(b+a)(b-a)} = \dfrac{8b+2a}{(b+a)(b-a)}.\\\\C)\ \dfrac{x^2}{x^2-a^2}-\dfrac{x}{x-a} = \dfrac{x^2}{(x-a)(x+a)}-\dfrac{x^{/x+a}}{x-a} = \dfrac{x^2-x(x+a)}{(x-a)(x+a)} = \dfrac{x^2-x^2-ax}{(x-a)(x+a)} =-\dfrac{ax}{(x-a)(x+a)}.\\\\$

$D)\ a^{/a+b} -\dfrac{ab}{a+b} =\dfrac{a(a+b)-ab}{a+b} = \dfrac{a^2+ab-ab}{a+b} = \dfrac{a^2}{a+b}.$

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