Предмет: Алгебра, автор: Nurzhan94

Помогите решить ................................

Приложения:

Simba2017: привет, ну это же просто

Simba2017: на 0 делить нельзя, значит в 1 и 4 -все кроме 0

Simba2017: 2) x^(9/2)=корень из x^9-подкоренное выражение больше или равно 0, значит и х такой же

Ответы

Автор ответа: Universalka

$1) \ f(x)=\dfrac{1}{x^{2} }-3$

Знаменатель дроби не должен равняться нулю , так как на ноль делить нельзя :

$x^{2}\neq0\\\\x\neq0\\\\Otvet:\boxed{D(f)\in(-\infty \ ; \ 0) \ \cup \ (0 \ ; \ -\infty)}$

$2) \ f(x)=x^{4,5}+2=x^{\frac{9}{2} }+2$

2 - чётное число , значит :

$\boxed{D(f)\in[0 \ ; \ +\infty)}$

$3) \ f(x)=x^{-2,5} +2=\dfrac{1}{x^{\frac{5}{2} } }+2\\\\Otvet:\boxed{D(f)\in(0 \ ; \ +\infty)}$

$4) \ f(x)=-\dfrac{1}{x^{2} } +4\\\\\boxed{D(f)\in(-\infty \ ; \ 0) \ \cup \ (0 \ ; \ +\infty)}$

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