Предмет: Алгебра, автор: vita8270

Відомо, що 2,4 < √6 < 2,5. Оцініть значення виразу:
$\frac{7-\sqrt{}6}{3}$

Ответы

Автор ответа: sergeevaolga5

Ответ:

$1,5<\frac{7-\sqrt{6}}{3}<15\frac{1}{3}$

Объяснение:

$2,4<\sqrt{6}<2,5\;\;|*(-1)\\\\-2,4>-\sqrt{6}>-2,5\\\\-2,5<-\sqrt{6}<-2,4\;\;|+7\\\\7-2,5<7-\sqrt{6}<7-2,4\\\\4,5<7-\sqrt{6}<4,6\; \; |:3\\\\\frac{4,5}{3}<\frac{7-\sqrt{6}}{3}<\frac{4,6}{3}\\\\1,5<\frac{7-\sqrt{6}}{3}<15\frac{1}{3}$

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