Предмет: Математика, автор: gordejsapoval

ПОМОГИТЕ ПОЖАЛУЙСТА УМОЛЯЮ

Приложения:

Ответы

Автор ответа: ksyuwi

( 1 )

$\displaystyle\\x+7\frac{8}{9}=9\frac{7}{12} \\\\\\x=9\frac{7}{12}-7\frac{8}{9}\\\\\\x=\frac{115}{12}-\frac{71}{9}\\\\\\x=\frac{115*3}{12*3}-\frac{71*4}{9*4}\\\\\\x=\frac{345}{36} -\frac{284}{36}\\\\\\x= \frac{61}{36}\\\\\\x= 1\frac{25}{36}$

Проверка:

$\displaystyle\\1\frac{25}{36}+7\frac{8}{9}=9\frac{7}{12}\\\\\\\frac{61}{36}+ \frac{71}{9}=9\frac{7}{12}\\\\\\\frac{61}{36}+\frac{284}{36}=9\frac{7}{12}\\\\\\\frac{345}{36}=9\frac{7}{12}\\\\\\9\frac{21}{36}=9\frac{7}{12}\\\\\\$

$\displaystyle\\9\frac{7}{12}=9\frac{7}{12}$

( 2 )

$\displaystyle\\x-7\frac{8}{19}= 4\frac{35}{38} \\\\\\x=4\frac{35}{38}+7\frac{8}{19} \\\\\\x=\frac{187}{38}+\frac{141}{19}\\\\\\x= \frac{187}{38}+\frac{141*2}{19*2}\\\\\\x=\frac{187}{38}+\frac{282}{38} \\\\\\x=\frac{469}{38}\\\\\\x= 12\frac{13}{38}$

Проверка:

$\displaystyle\\12\frac{13}{38}-7\frac{8}{19}=4\frac{35}{38}\\\\\\\frac{469}{38}-\frac{141}{19}=4\frac{35}{38}\\\\\\\frac{469}{38}-\frac{282}{38}=4\frac{35}{38}\\\\\\\frac{187}{38}=4\frac{35}{38}\\\\\\4\frac{35}{38}=4\frac{35}{38}$