Предмет: Математика, автор: satohinamasa45588

СРОЧНО ДАЮ 80 БАЛОВ


висота рівнобічної трапеції дорівнює 37.Знайдіть кут який утворює висота трапеції пррведена з вершини тупого кута,з бічною стороною ​


as11111: В такой формулировке задача решения не имеет, существует бесчисленное множество равнобочных трапеций с высотой равной 37
satohinamasa45588: извините,я перепутала.вместо 37,43 градуса
as11111: опять не понятно, дана высота или угол? если угол, то какой?
satohinamasa45588: высота равносторонней трапеции проведена с вершины тупого угла, образует с боковой стороной угол 43 ° .Знайдить углы трапеции

Ответы

Автор ответа: as11111
1

Ответ:

∠CDA=∠BAH=47°

∠BCD=∠ABC=133°

Пошаговое объяснение:

∠ABH=43°

Из прямоугольного ΔABH находим ∠BAH=47°

∠ABC=∠ABH+∠HBC=43°+90°=133°

Т.к. углы при основаниях равнобедренной трапеции равны, то

∠CDA=∠BAH=47°

∠BCD=∠ABC=133°

Приложения:

as11111: с каким?
satohinamasa45588: сейчас
satohinamasa45588: могут углы трапеции в последовательном порядке относится как 5: 1: 4: 5
satohinamasa45588: и 5:1:3:3
as11111: в первом случае нет во втором да
as11111: сумма смежных углов при каждой боковой стороне равна 180, соответственно они должны быть равны
as11111: 5+1 не равен 4+5
as11111: 5+1=3+3
satohinamasa45588: спасибо вам огромное
satohinamasa45588: я очень благодарна
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