Предмет: Химия, автор: 84vavassavav48

Який об'єм займає водень массою 44г?

Ответы

Автор ответа: unezhewaoxnw6u

Ответ:

Объяснение:

m(CO2)=44г

V(CO2)-?

Молекулярная масса СО2 =44г/моль

Молярный объем газов при нормальных условиях = 22,4л/моль

V(CO2)=n×Vm

n(CO2)=m/M

V(CO2)=n×Vm=(m/M)×Vm=(44×22.4)/44=22,4л

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