Предмет: Математика, автор: lena858526

Площадь прямоугольника ABCD = 18 см2, а площадь треугольника АВD равна:
А) 2 см2; Б) 36 см2; В) 9 см2.

Ответы

Автор ответа: mankanastia

1

Ответ:

9см2.

Пошаговое объяснение:

SABD=18:2=9см2.

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