Предмет: Алгебра, автор: tochtonudo

ПОМОГИТЕ ОООЧЕНЬ СРОЧНО!!!!!!! ПОЖАААААЛУЙСТА!!!
запишите формулу:
№1
(a-b)(a+b)
(a+b)в квадрате
(a-b)в квадрате
№2
представьте в виде многочлена:
а) (2-n)в квадрате
б) (5a+4c)в квадрате
в) (7+x)(x-7)
№3
разложите на множители:
а)25-с в квадрате
б)4m в квадрате +20mn+25n в квадрате
№4
а)21 в квадрате +42*39+39в квадрате
б)85 в квадрате
в)43*37

Ответы

Автор ответа: paveltop186
0

Ответ:

Объяснение:

Номер 1

(a-b)(a+b)=a^2-b^2

(A+b)^2=a^2+2ab+b^2

(A-b)^2=a^2-2ab+b^2

Приложения:
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