Предмет: Геометрия, автор: Dzidzoeva

Решите треугольник АВС если угол В=30 угол С=105 ВС=3 корень из 2

Ответы

Автор ответа: Гоша68

A=180-30-105=45

AC/sinB=BC/sinA

AC=BCsinB/sinA=3sqrt(2)0,5/(sqrt(2)/2)=3

AB/sin105=AC/sin30

AB=ACSIN105/sin30=3cos15/0,5=6cos15=3(sqrt(3)+1)/sqrt(2)

cos15=(sqrt(3)+1)/(2sqrt(2))

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