решите уравнение........... ​

Ответ:

x=±π/8+πn/2+π/24; n∈Z

Пошаговое объяснение:

f'(x)=cos(4x-π/6))*(4x-π/6)'=4*cos(4x-π/6)

по формуле (sin(kx+b))'=k*cos(kx+b)

4*cos(4x-π/6)=0

cos(4x-π/6)=0

(4x-π/6)=±arccos0+2πn; n∈Z

4x=±π/2+2πn+π/6; n∈Z

x=±π/8+πn/2+π/24; n∈Z