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Ответ:

1)

24c

18bc

=

4∗6c

3b∗6c

=

4

3b

2)

15by

25a2y

=

3b∗5y

10a∗5y

=

3b

10a

15by

25a

2

y

=

3b∗5y

5a

2

∗5y

=

3b

5a

2

3)

6ac

24a2y

=

c∗6a

8y∗6a

=

c

8y

6ac

24a

2

y

=

c∗6a

4ay∗6a

=

c

4ay

4)

21xy3

27x2y

=

7∗9xy

6∗9xy

=

7

6

21xy

3

27x

2

y

=

7y

2

∗3xy

9x∗3xy

=

7y

2

9x

Пошаговое объяснение:

1) (18bc)/(24c) = (3b * 6c)/(4 * 6c) = (3b)/4

2) (25a * 2y)/(15by) = (10a * 5y)/(3b * 5y) = (10a)/(3b)

(25a ^ 2 * y)/(15by) - (5a ^ 2 * 5y)/(3b * 5y) - (5a ^ 2)/(3b)

3) (24a * 2y)/(6ac) = (8y * 6a)/(c * 6a) = (8y)/c

(24a ^ 2 * y)/(6ac) = (4ay * 6a)/(c * 6a) = (4ay)/c

4) (27x * 2y)/(21xy * 3) = (6 * 9xy)/(7 * 9xy) = 6/7