Предмет: Геометрия, автор: kurilldmitrev20054

3. В треугольнике ABC AB = BC. Вд - перпендикуляр. Угол Свд = 50°, АД =4. Найдите угол ABC и сторону AC.

Ответы

Автор ответа: schoolmol

0

АВС равнобедренный, углы при основании равны АВС 50
ВD перпендикуляр, значит высота и медиана АС=2•АD=8
Ответ 50, 8

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