Предмет: Физика, автор: Ghbfeh611

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Сколько атомов радиоактивного элемента распадется за 23 ч из 10⁶ атомов? Период полураспада данного элемента 92ч.

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Автор ответа: Hecarim

N0 = 10⁶ атомов
t = 23 ч
T = 92 ч
N0 - N - ?

Закон радиоактивного распада: N = N0 * 2^(-t/T) = 10⁶ * 2^(-23/92) =
=10⁶ * 2^(-0,25) = $\frac{10^6}{\sqrt[4]{2}}$ = 840 896 атомов останется после 23 часов

Получается что распалось 1000 000 - 840 896 = 159 104 атомов распалось

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Primitive counting.
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Помогите, пожалуйста Сколько атомов радиоактивного элемента распадется за 23 ч из 10⁶ атомов? Период полураспада данного элемента 92ч.

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Помогите, пожалуйста

Сколько атомов радиоактивного элемента распадется за 23 ч из 10⁶ атомов? Период полураспада данного элемента 92ч.