Предмет: Алгебра, автор: Аноним

ДАЮ 100 БАЛЛОВ Поясніть, чому системи рівнянь не мають розв'язків:
$1) \left \{ {{3x+y=5} \atop {3x+y=-5}} \right. 2) \left \{ {{2x-3y=5} \atop {x-1,5y=5}} \right. 3)\left \{ {{-x+2y=3} \atop {2x-4y=6}} \right.$

Ответы

Автор ответа: orakul96

В 1 системе угловые коэф. при х одинаковые. Это значит что графики паралельны и не имеют решений.

2. если мы поделим 1 уравнение системы на 2, то выйдет:

х-1,5у=2,5

Поэтому объяснение такое же как и в 1 системе

3. Поделим 2 уравнение на -2

-х+2у=-3

Замечаем что угловые коэф. при х опять одинаковые, поэтому объяснение такое же

Надеюсь помог

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