Предмет: Геометрия, автор: Anyathemy

В остроугольном треугольнике МNР биссектриса угла М пересекает высоту NК в

точке О, причём ОК = 8 см. Найдите расстояние от точки О до прямой МN.​

Ответы

Автор ответа: ludmilaksenija2005
1

Ответ:

8 см

Объяснение:

ОL=?

Тр-к MLO и тр-к MKO

<MLO=<MKO =90 градусов

<ОМL=<OMK - по условию(МО биссектриса угла М)

МО - общая

Тр-ки равны по гипотенузе и острому углу, значит соответствующие элементы равны, следовательно, ОL=OK=8 cм

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