Предмет: Математика, автор: mayeranika13

Помогите!!!! Задание на фото!!

Приложения:

Ответы

Автор ответа: GoldenVoice

Ответ:

1) 4,75;

2) $5\frac{{21}}{{22}}$

Пошаговое объяснение:

№ 1

$1)\,\,\displaystyle\frac{{11}}{{ - 9 + 2\displaystyle\frac{1}{3}}} = \displaystyle\frac{{11}}{{ - 9 + \displaystyle\frac{7}{3}}} = 11:\displaystyle\frac{{ - 27 + 7}}{3} = 11 \cdot \left( { - \displaystyle\frac{3}{{20}}} \right) = - \displaystyle\frac{{33}}{{20}};$

$2)\,\, - \displaystyle\frac{{33}}{{20}} - \displaystyle\frac{1}{6} \cdot 12,5 + 1\displaystyle\frac{{13}}{{30}} = - \displaystyle\frac{{33}}{{20}} - \displaystyle\frac{1}{6} \cdot \displaystyle\frac{{25}}{2} + \displaystyle\frac{{43}}{{30}} = \displaystyle\frac{{ - 99 - 125 + 86}}{{60}} = - \displaystyle\frac{{23}}{{10}};$

$3)\,\, - \displaystyle\frac{{23}}{{10}}:( - 0,23) = \displaystyle\frac{{23}}{{10}}:\displaystyle\frac{{23}}{{100}} = \displaystyle\frac{{23}}{{10}} \cdot \displaystyle\frac{{100}}{{23}} = 10;\\\\4)\,\,10 - 0,005 \cdot 1050 = 10 - \displaystyle\frac{1}{{200}} \cdot 1050 = 10 - \displaystyle\frac{{21}}{4} = \displaystyle\frac{{40 - 21}}{4} = \displaystyle\frac{{19}}{4} = 4{,}75.$

№ 2

$1)\,\,6\displaystyle\frac{{13}}{{22}} + 5\displaystyle\frac{5}{{11}}:( - 4) = 6\displaystyle\frac{{13}}{{22}} - \displaystyle\frac{{60}}{{11}}:4 = 6\displaystyle\frac{{13}}{{22}} - \displaystyle\frac{{30}}{{22}} = 5\displaystyle\frac{5}{{22}};\\$

$2)\,\,5\displaystyle\frac{5}{{22}} - \displaystyle\frac{5}{{132}}:\left( { - \displaystyle\frac{1}{6}} \right) = 5\displaystyle\frac{5}{{22}} + \displaystyle\frac{5}{{132}} \cdot 6 = 5\displaystyle\frac{5}{{22}} + \displaystyle\frac{5}{{22}} = 5\displaystyle\frac{5}{{11}};\\$

$3)\,\,5\displaystyle\frac{5}{{11}} + {\left( { - \displaystyle\frac{5}{6}} \right)^2}:1\displaystyle\frac{7}{{18}} = 5\displaystyle\frac{5}{{11}} + \displaystyle\frac{{25}}{{36}}:\displaystyle\frac{{25}}{{18}} = 5\displaystyle\frac{5}{{11}} + \displaystyle\frac{1}{2} = 5 + \displaystyle\frac{{10 + 11}}{{22}} = 5\displaystyle\frac{{21}}{{22}}.$