Предмет: Алгебра, автор: VelantisXL

((a ^ 2 * b ^ 3)/(3c ^ 5)) ^ 4

Приложения:

Ответы

Автор ответа: axatar
2

Ответ:

\displaystyle \tt \left (\frac{a^2 \cdot b^3}{3 \cdot c^5} \right )^4=\frac{a^{8} \cdot b^{12}}{81 \cdot c^{20}}

\displaystyle \tt \frac{x^2 -4 \cdot x}{8 \cdot x^2} :\frac{x -4}{4 \cdot x} =\frac{1}{2}

\displaystyle \tt \frac{5 \cdot x^4 \cdot y^3}{x+3}:(10 \cdot x^2 \cdot y^3)=\frac{5 \cdot x^4 \cdot y^3}{x+3}:\frac{10 \cdot x^2 \cdot y^3}{1}=\frac{x^2 }{2 \cdot (x+3) }

Объяснение:

Перевод:

Возведите к степени дробь \displaystyle \tt \left (\frac{a^2 \cdot b^3}{3 \cdot c^5} \right )^4;

Выполните деление: \displaystyle \tt \frac{x^2 -4 \cdot x}{8 \cdot x^2} :\frac{x -4}{4 \cdot x}  ;

Найдите частное  \displaystyle \tt \frac{5 \cdot x^4 \cdot y^3}{x+3} и \displaystyle \tt 10 \cdot x^2 \cdot y^3.

Нужно знать свойства:

\displaystyle \tt 1) \; \left (\frac{a^n}{b^k} \right )^m=\frac{a^{n \cdot m}}{b^{k \cdot m}};

\displaystyle \tt 2) \; \frac{a}{b}:\frac{c}{d}=\frac{a}{b} \cdot \frac{d}{c}.

Решение.

\displaystyle \tt \left (\frac{a^2 \cdot b^3}{3 \cdot c^5} \right )^4=\frac{a^{2 \cdot 4} \cdot b^{3 \cdot 4}}{3^4 \cdot c^{5 \cdot 4}}= \frac{a^{8} \cdot b^{12}}{81 \cdot c^{20}}.

\displaystyle \tt \frac{x^2 -4 \cdot x}{8 \cdot x^2} :\frac{x -4}{4 \cdot x} =\frac{x^2 -4 \cdot x}{8 \cdot x^2} \cdot \frac{4 \cdot x}{x-4} =\frac{(x -4) \cdot x}{2 \cdot 4 \cdot x^2} \cdot \frac{4 \cdot x}{x-4} =\\\\=\frac{(x -4) \cdot 4 \cdot x^2}{2 \cdot 4 \cdot x^2 \cdot (x-4)} =\frac{1}{2}.

\displaystyle \tt \frac{5 \cdot x^4 \cdot y^3}{x+3}:(10 \cdot x^2 \cdot y^3)=\frac{5 \cdot x^4 \cdot y^3}{x+3}:\frac{10 \cdot x^2 \cdot y^3}{1}=\frac{5 \cdot x^4 \cdot y^3}{x+3} \cdot \frac{1}{10 \cdot x^2 \cdot y^3}=\\\\=\frac{5 \cdot x^4 \cdot y^3}{(x+3) \cdot 10 \cdot x^2 \cdot y^3} =\frac{5 \cdot x^2 \cdot x^2 \cdot y^3}{(x+3) \cdot 2 \cdot 5 \cdot x^2 \cdot y^3} =\frac{x^2 }{2 \cdot (x+3) } .

#SPJ1

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