Предмет: Алгебра, автор: morganelos

Решите уравнение
2(2y+3) = y+3+y^2-1

Ответы

Автор ответа: Universalka
0

\displaystyle\bf\\2(2y+3)=y+3+y^{2}-1\\\\4y+6=y+3+y^{2} -1\\\\y^{2}+y-4y-6+3-1=0\\\\y^{2} -3y-4=0\\\\D=(-3)^{2} -4\cdot(-4)=9+16=25=5^{2} \\\\\\y_{1} =\frac{3-5}{2} =-1\\\\\\y_{2} =\frac{3+5}{2} =4\\\\\\Otvet \ : \ -1 \ ; \ 4

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