Предмет: Алгебра, автор: serhiikoshevoi13

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Автор ответа: zanbolkobeev999

1

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Объяснение:

$1)y^{|}=7*(9-6x)^6=42(9-6x)^5\\2)y^{|}=((x^3-5x)^{^-7})^{|}=-7(x^3-5x)^{-8}*(3x^2-5)=-\frac{7(3x^2-5)}{(x^3-5x)^8} \\3)y^{|}=\frac{7}{2\sqrt{7x-11} } \\4)y^{|}=(x^6-11x)^\frac{1}{6}=\frac{1}{6}(x^6-11x)^{-\frac{5}{6}}*6x^5-11=\frac{6x^5-11}{6\sqrt[6]{(x^6-11x)^5} }$

serhiikoshevoi13: Спасибо большое

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