Предмет: Алгебра, автор: rusfrogqe

Допоможіть будь ласка треба зробити зараз на колінах прошу

Приложения:

poczatek: актуально?

rusfrogqe: Так

rusfrogqe: Дуже потрібно

Ответы

Автор ответа: poczatek

1

Ответ:

1)Б

2)В

3)Г

4)Б

5)Г

6)А

Объяснение:

7) $\frac{5x}{x-2} -\frac{10}{x-2}$

$\frac{5x-10}{x-2}$

$\frac{5(x-2)}{x-2}$ = 5

Дiлимо на (x-2) и ответ 5

8)

$\frac{4-m}{m-3}+\frac{2m-5}{3-m} \\\frac{4-m}{m-3}+\frac{2m-5}{-(m-3)}\\ \frac{4-m}{m-3}-\frac{2m-5}{m-3}\\ \frac{4-m-(2m-5)}{m-3}\\ \frac{4-m-2m+5}{m-3}\\\frac{9-3m}{m-3}\\ \frac{-3m+9}{m-3} \\ \frac{-3(m-3)}{m-3}\\$ = -3

Дiлимо на m-3 и ответ -3

9)

$\frac{3n^{2} }{n-6}-3n\\ \frac{3n^2-3n(n-6)}{n-6}\\ \frac{3n^2-3n^2+18n}{n-6}\\ \frac{3n^2-3n^2+18n}{n-6} \\\frac{18n}{n-6}$

Так як сума 3n^2 = 0, тому вiдповiдь 18n/n-6

10)

$\frac{2m+1}{3m-2}+\frac{3m^2+m-2}{9m^2-12m+4}\\ \frac{2m+1}{3m-2} -\frac{3m^2+3m-2m-2}{(3m-2)^2}\\ \frac{2m+1}{3m-2}-\frac{3m(m+1)-2(m+1)}{(3m-2)^2}\\ \frac{2m+1}{3m-2} -\frac{(m+1)(3m-2)}{(3m-2)^2} \\\frac{2m+1}{3m-2}-\frac{m+1}{3m-2}\\\frac{2m+1(m-1)}{3m-2}\\ \frac{2m+1-m-1}{3m-2} \\\frac{2m-m}{3m-2}\\ \frac{m}{3m-2}$

11)

$\frac{a-12}{a^2+4a} -\frac{a-4}{a} +\frac{a}{a+4}\\ \frac{a-12-(a+4)(a-4)+a^2}{a(a+4)}\\ \frac{a-12-(a^2-16)+a^2}{a(a+4)}\\ \frac{a-12-a^2+16+a^2}{a(a+4)}\\ \frac{a-12+16}{a(a+4)} \\\frac{a+4}{a(a+4)}\\ \frac{1}{a}$

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