Предмет: Алгебра, автор: Kristino4ka210

Найдите производную функции пожалуйста на завтрашний день нужно!!!!
б) ϑ(x)=2/x³(в кубе) - x корень х

в)g(x) = 4 sin x и вычислите g' (-2п/3)

г)h(x)=2-3x/x+2 и вычислите h'(-1)

Ответы

Автор ответа: No4nOi

0

б) $f(x)= frac{2}{x^3} -x sqrt{x} =2*x^-3-x^{ frac{3}{2}$
$f'(x)=2*(-3)x^{-4}- frac{3}{2} x^{ frac{1}{2}}=-6x^{-4}- frac{3}{2} x^{ frac{1}{2}}$

в) $f'(x)=4sinx$
$f'(x)=4cosx$
$f'(- frac{2p}{3})=4cos(- frac{2p}{3})=4cos(p- frac{2p}{3})=4cos( frac{p}{3})=4* frac{1}{2} =2$

г) $f(x)= frac{2-3x}{x+2}$
$f'(x)= frac{-3(x+2)-(2-3x)}{(x+2)^2}$
$f'(-1)= frac{-5+3}{1}=-2$

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