Предмет: Алгебра, автор: Lorkin

Найдите корни уравнения x^2+4x-12=0

Ответы

Автор ответа: Лето2012

x^2+4x-12=0
D= 4^2-4*1*(-12)= 64 извлекаем корень=8
x1= -4-8/2= -6
x2=-4+8/2= 2
Ответ -6; 2

Автор ответа: Yulenkaandr

x^2+4x-12=0
x1+x2= -4
x1*x2= -12

x1= -6
x2= 2

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