Предмет: Химия, автор: ainurai

В эвдиометре взорвали смесь, состоящую из 24мл водорода и 15мл кислорода, при этом образовалась вода. Какой газ и в каком объеме остался после взрыва в смеси?

Ответы

Автор ответа: dashkanaroch

2H2+O2=2H2O

n(H2)=V(H2)/Vm=0.024л/22.4лмоль=0.00107моль

n(O2)=V(O2)/Vm=0.015л/22.4лмоль=0.00067моль

по уравнению реакций n(H2):n(O2)=2:1и на 0.00107моль (H2)должно приходиться 0.000535 (O2) значит O2 в избытке

n(ocm. O2)=n(O2)-n(npop. O2)=0.00067моль-0.000535моль=0.000135моль

V(ocm. O2)=n(ocm. O2)*Vm=0.000135моль*22.4лмоль=0.003024л=3.024мл

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