Предмет: Химия, автор: olia23

Чему равен эквивалент мышьяковой кислоты в данной реакции H3AsO4 + 2NaOH = Na2HAsO4 + 2H2O

Ответы

Автор ответа: тайная

Э(H₃AsO₄) = 1423 = 47,33 гмоль
экв. кислоты = молярная массаосновность
в уравнении: замещение на 2 атома Н, следовательно f'экв12
H₃AsO₄ + 2NaOH = Na₂HAsO₄ + 2H₂O
пересчет по уравнению:
Э(H₃AsO₄) = 142 · 12 = 71 гмоль

Автор ответа: Аноним

Я тебе объяснять не буду - не позорься.

Автор ответа: тайная

не знаешь))?

Автор ответа: Аноним

Читай выше мои комменты и не раздражай.

Автор ответа: Аноним

1) В данной р-ии в мол-е H3AsO4 зам-ся 2 атома (точнее иона) H, след-но, ф.э. H3AsO4 (М = 142 г/моль) = 1/2;

2) т.о. М экв. H3AsO4 = 142*(1/2) = 71 г/моль.

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