Предмет: Алгебра, автор: vikaiobidze

3sin в квадрат x+7 cos x -3=0

Ответы

Автор ответа: levon52

3sin2x+7cosx-3=0

3(1-cos 2x)+7cosx-3=0

3-3cos2x+7cosx-3=0

3cos2x-7cosx=0

cosx(3cosx-7)=0

cosx=0

x1=п/2+2пn

3cosx-7=0

cosx=7/3 – (сторонний корень, 0<cosx<1)

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