Предмет: Химия, автор: kaXio

Какая масса этана должна вступить в реакцию с бромом,чтобы в результате реакции образовалось 4 г дибромэтана??

Ответы

Автор ответа: karpickiydim
0
С2Н6+2 Br2 = C2H4Br2+2 HBr
М (С2H4Br2) = 12x2+4x1+80x2 = 188 г/моль
(ню) (С2Н4Br2) = 4/188 = 0,0213 моль
По реакции получается, что этана столько же моль, следовательно:
М (С2Н6) = 24+6=30 г/моль
m(С2Н6)=0,0213х30 = 0,639 г
Автор ответа: karpickiydim
0
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