Предмет: Алгебра, автор: aleks12092002

Помогите пожалуйста,нужно срочно решить

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Ответы

Автор ответа: oksik1970

1 вариант
▪1.

а)
$\frac{29}{6} = 4 \frac{5}{6}$
б)
$\frac{17}{8} = 2 \frac{1}{8}$
в)
$\frac{40}{7} = 5 \frac{5}{7}$
г)
$\frac{15}{5} = 3$
д)
$\frac{40}{8} = 5$
▪2.

$2 \frac{1}{3} = \frac{7}{3}$
$5 \frac{5}{6} = \frac{35}{6}$
$6 \frac{7}{8} = \frac{55}{8}$
$5 = \frac{5}{1}$
$8 \frac{3}{7} = \frac{59}{7}$

▪3.

$\frac{9}{12} = \frac{3}{4}$
$\frac{30}{42} = \frac{5}{7}$
$\frac{5}{90} = \frac{1}{18}$
$\frac{35}{49} = \frac{5}{7}$
$\frac{81}{108} = \frac{3}{4}$

▪4.

$\frac{4}{15} + \frac{3}{5} = \frac{4 + 9}{15} = \frac{13}{15}$
$\frac{3}{8} + \frac{7}{20} = \frac{15 + 14}{40} = \frac{29}{40}$
$\frac{3}{16} + \frac{1}{24} = \frac{9 + 2}{48} = \frac{11}{48}$
$1 \frac{9}{14} + 2 \frac{1}{7} = 3 \frac{9 + 2}{14} = 3 \frac{11}{14}$
$1 \frac{5}{8} + 2 \frac{9}{16} = 3 \frac{10 + 9}{16} = 3 \frac{19}{16} = 4 \frac{3}{16}$

▪5.

$\frac{7}{10} - \frac{1}{2} = \frac{7 - 5}{10} = \frac{2}{10} = \frac{1}{5}$
$\frac{13}{20} - \frac{3}{8} = \frac{26 - 15}{40} = \frac{11}{40}$
$\frac{13}{14} - \frac{5}{42} = \frac{39 - 5}{42} = \frac{34}{42} = \frac{17}{21}$
$3 \frac{1}{6} - 2 \frac{1}{12} = 1 \frac{2 - 1}{12} = 1 \frac{1}{12}$
$5 \frac{1}{14} - 3 \frac{2}{7} = 2 \frac{1 - 4}{14} = 2 - \frac{3}{14} = 1 \frac{14 - 3}{14} = 1 \frac{11}{14}$

▪6.

$\frac{2}{3} \times \frac{1}{4} = \frac{1}{3 \times 2} = \frac{1}{6}$
$\frac{2}{5} \times \frac{15}{16} = \frac{3}{8}$
$1 \frac{1}{6} \times \frac{6}{7} = \frac{7 \times 6}{6 \times 7} = 1$
$\frac{5}{8} \times 1 \frac{3}{7} = \frac{5 \times 10}{8 \times 7} = \frac{5 \times 5}{4 \times 7} = \frac{25}{28}$
$3 \frac{3}{7} \times 1 \frac{1}{6} = \frac{24 \times 7}{7 \times 6} = \frac{4}{1} = 4$

▪7.

$\frac{3}{14} \div \frac{2}{7} = \frac{3 \times 7}{14 \times 2} = \frac{3}{4}$
$\frac{7}{12} \div \frac{1}{3} = \frac{7 \times 3}{12 \times 1} = \frac{7}{4} = 1 \frac{3}{4}$
$\frac{3}{4} \div 1 \frac{7}{8} = \frac{3}{4} \div \frac{15}{8} = \frac{3 \times 8}{4 \times 15} = \frac{2}{5}$
$1 \frac{1}{2} \div \frac{3}{5} = \frac{3 \times 5}{2 \times 3} = \frac{5}{2} = 2 \frac{1}{2}$
$2 \frac{2}{3} \div 1 \frac{1}{3} = \frac{8}{3} \div \frac{4}{3} = \frac{8 \times 3}{3 \times 4} = 2$

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